If an AC transformer secondary has twice as many loops as the primary, what will be the voltage outcome?

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When an alternating current (AC) transformer has a secondary winding with twice as many loops (or turns) as the primary winding, it operates on the principle of electromagnetic induction, which is governed by Faraday's law. This law states that the induced voltage in a coil is directly proportional to the rate of change of magnetic flux through the coil and the number of loops of the wire.

In this scenario, with the secondary having twice as many loops as the primary, the voltage in the secondary will be higher than in the primary. This relation is expressed in terms of the turns ratio: the voltage across the primary and secondary poles is proportional to the number of turns. Therefore, if the secondary has twice the number of turns, the voltage in the secondary will be doubled compared to the voltage in the primary.

Regarding amperage, according to the conservation of energy in the transformer, if the voltage increases, the current (amperage) must decrease for power to remain constant (assuming negligible losses). Power is the product of voltage and current (P = V × I). If the voltage on the secondary side doubles due to the increased number of loops, the amperage will decrease to maintain the same power level.

Thus, the scenario described results in a

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